1.suatu fungsi h(x) = ax + b. jika h(2) = -5 dan h(-1) = 7, maka nilai a dan b adalah.... 2.Fungsi f : x -> 2x + 1 dengan daerah asal {1,2,3}, maka daerah hasil

1.) h(x) = ax + b
h(2) = a(2) + b = - 5 .... 2a + b = - 5
h(-1) = a (-1) + b = 7 .... - a + b = 7

2a + b = - 5
- a + b = 7
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3a = - 12
a = - 12/3
a = - 4

2a + b = - 5
2(-4) + b = - 5
-8 + b = -5
b = -5 +8
b = 3

jadi a = - 4 dan b = 3

2.) f : x -> 2x + 1
f(1) = 2(1) + 1 = 3
f(2) = 2(2) + 1 = 5
f(3) = 2(3) + 1 = 7
daerah hasil {3,5,7}