tolong ya musti dikumpul besok kalo gk gk bisa ikut to2

rumus dasar yang digunakan untuk mengerjakan dua soal di atas

F = (k q1•q1)/r²

65. q1 = 2 x 10^-6C
q2 = 3 x 10^-6 C
F = 135 N
k = 9 x 10^9 Nm²/C²

F = (k q1•q2) /r²
135 = (9 x 10^9 x 2 x 10^-6 x 3 x 10^-6)/r²
135 = (54 x 10^-3) / r²
r² = (54 x 10^-3)/135
r² = 0.4 x 10^-3 = 4 x 10^-4
r = √(4 x 10^-4) = 4 x 10^-2 = 0.02 m = 2 cm

66. r = 45 cm = 0.45 m
F = 1.6 N
k = 9 x 10^9 Nm²/C²

F = (k q1•q2) /r²
q1 = q2 = q
1.6 = (9 x 10^9 x q²) / (0.45)²
1.6 x (0.45)² = 9 x 10^9 x q²
0.324 = 9 x 10^9 x q²
q² = 0.324/ (9 x 10^9)
q² = 0.036 x 10^-9 = 36 x 10^-12
q = √(36 x 10^-12) = 6 x 10^-6 C
q = 6 μC