Matematika

Pertanyaan

hitung nilai eksak dari sin 20 sin 40 sin 60 sin 80

1 Jawaban

  • sin(20)sin(40) = (1/2)[cos(20) - cos(60)]
    => sin(20)sin(40)sin(80)
    = (1/2)[cos(20) - cos(60)]sin(80)
    = (1/2)[cos(20)sin(80) - cos(60)sin(80)]
    = (1/2)[(1/2)(sin(100)+sin(60)) - (1/2)(sin(140)+sin(20))]
    = (1/4)[sin(80) + sin(60) - sin(40) - sin(20)]
    = (1/4)sin(60)
    = akar(3)/8

    NOTE: sin(80) - sin(40) - sin(20) = sin(60+20) - sin(60-20) - sin(20) = 2cos(60)sin(20) - sin(20) = 0

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