Diketahui sistem persamaan linear tiga variabel berikut. 2x+3y=2z=12 x+y-2z=7 x+y-z=5

x = 1
y = 2
z = -2

Maaf kalo salah.

2x+3y-2z=12 (pers. 1)
x+y-2z=7 (Pers. 2)
x+y-z=5 (pers. 3)
eliminasi pers. 2 & 3
(x+y-2z=7)-(x+y-z=5)
=-z=2/ z=-2
eliminasi pers. 1 & 2
(2x+3y-2z=12)-(2x+2y-4z=14)
=y+2z=-2 (pers 4)
z=-2 → pers 4
y+2(-2)=-2
y+(-4)=-2
y=-2+4
y=2
y=2 & z=-2 → pers. 2
x+2-2(-2)=7
x+2-(-4)=7
x+6=7
x=7-6
x=1
HP={(1,2,-2)}