Matematika

Pertanyaan

Simpangan baku dari data 6,4,5,6,5,7,8,7

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  • Statistika

    Data: 6, 4, 5, 6, 5, 7, 8, 7
    n = 8

    x bar = ∑x / n
    x bar = (6 + 4 + 5 + 6 + 5 + 7 + 8 + 7) / 8
    x bar = 48 / 8
    x bar = 6

    S = √[(∑x - x bar)² / n]
    S = √[((6 - 6)² + (4 - 6)² + (5 - 6)² + (6 - 6)² + (5 - 6)² + (7 - 6)² + (8 - 6)² + (7 - 6)²) / 8]
    S = √[(0 + 4 + 1 + 0 + 1 + 1 + 4 + 1) / n]
    S = √(12 / 8)
    S = √1,5
    S = 1,224

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