Panjang garis pelukis sebuah kerucut 26 cm jika tinggi kerucut 24 cm, tentukan: A. luas Selimut kerucut B. Luas Kerucut C. Volume kerucut

s = 26 cm
t = 24 cm
A) Lsk
B) Lk
C)Vk

A)
r^2 = s^2 - t^2
r^2 = 26^2 - 24^2
r^2 = 676 - 576
r^2 = 100
r = V100
r = 10 cm

Lsk = phi × r × s
Lks = 3,14 × 10 × 26
Lks = 816,4 cm^2

B)
Lk = La + Lsk
Lk = (phi × r^2) + (phi × r × s)
Lk = (3,14 × 10^2) + (3,14 × 10 × 26)
Lk = (3,14 × 100) + 816,4
Lk = 314 + 816,4
Lk = 1130,4 cm^2

C)
Vk = 1/3 × phi × r^2 × t
Vk = 1/3 × 3,14 × 10^2 × 24
Vk = 1/3 × 3,14 × 100 × 24
Vk = 2512 cm^3