f(x)=ax+b. jika f(-2)=14 dan f(3)=-1. nilai f(7)-f(10) adalah

-2a +b = 14
3a + b = -1
----------------  -
-5a = 15
a = -3

-2(-3) + b = 14
b = 14 - 6
b = 8
 f (7) = -3(7) +8
        = -13
f (10) = -3(10) + 8
         = -22
f(7) - f(10 ) = -13 - (-22)
                  = 9

f(x)=ax+b
f(-2)=-2a+b=14
f(3) =3a+b=-1
-2a+b=14
3a+b=-1. _
-5a=15
a=15/-5=-3
ax+b=-1
-3(3)+b=-1
-9+b=-1
b=9-1=8
f(7)=ax+b=-3(7)+8=-21+8=-13
f(10)=ax+b=-3(10)+8=-30+8=-22
f(7)-f(10)=-13-(-22)=-13+22=9